18b^2-24b-192=0

Solution for 18b^2-24b-192=0 equation:

18b^2-24b-192=0

a = 18; b = -24; c = -192;
Δ = b2-4ac
Δ = -242-4·18·(-192)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-120}{2*18}=\frac{-96}{36}
=-2+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+120}{2*18}=\frac{144}{36}
=4
$